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Wednesday, February 5, 2014


Question#03A

We have to find out the delay;

Link=36000m long

1Gbps speed & 10MB size

D=speed of light=36000/299792458

=.00012 ms

M=10 MB = 83886080 bits

R=1Gbps=1000, 000,000 bps

L= (M/R) +D= (83886080/1000, 000,000) +0.00012

=.084+.00012=.08412ms

Question#03B

Long is 2m

10bps speed

D=2/2997992458=.00000667 ms

L= (M/R) +D

= (8388608/10) +.00000667

=8388608+.00000667=8388608

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